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7x^2+4x-3=90.4
We move all terms to the left:
7x^2+4x-3-(90.4)=0
We add all the numbers together, and all the variables
7x^2+4x-93.4=0
a = 7; b = 4; c = -93.4;
Δ = b2-4ac
Δ = 42-4·7·(-93.4)
Δ = 2631.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{2631.2}}{2*7}=\frac{-4-\sqrt{2631.2}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{2631.2}}{2*7}=\frac{-4+\sqrt{2631.2}}{14} $
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